tomachello

4 ms·

1. 1.▲
   Ask HN: What's the coolest, non-useful project you've built

   3 points by tomachello 4y ago|2 comments
2. 2.▲
   by tomachello 4y ago

   They just need one prisoner to guess correctly - then they all win. Regarding the base case scenario - if each prisoner guesses randomly, each has a 1/100 chance of guessing correctly, and hence they have an expected number of exactly
3. 3.▲
   by tomachello 4y ago

   No, only one. Think about it this way - if the warden randomly generates their numbers, each prisoner has a 1/100 chance of guessing it right. So best case scenario is exactly one gets it right, which is actually possible.
4. 4.▲
   Ask HN: What's your favorite math/logic puzzle?

   5 points by tomachello 4y ago|7 comments