tgingold

5 ms·

1. 1.▲
   by tgingold 3y ago

   For a first approximation, you can assume A->B and B->A travel times are equal. And because optical links are used, the asymmetry is mainly due to the wavelength difference which is known.
2. 2.▲
   by tgingold 3y ago

   In a white-rabbit network you don't need atomic clocks on each node. One atomic clock is enough, its frequency is distributed over the network.
3. 3.▲
   by tgingold 3y ago

   Only over fiber. Copper SFPs are not deterministic enough to precisely synchronize networks.
4. 4.▲
   by tgingold 3y ago

   No, we don't know the distance between nodes (although we could deduce it). But using timestamps, we can know the round-trip time. See https://www.ohwr.org/project/white-rabbit/uploads/2b9d42b664... (pag