qzzi

5 ms·

1.
by qzzi 2mo ago
I clicked on 2 links on the main page in the Learn F* section...
2.
by qzzi 6mo ago
1.1.1.1 is simply a free DNS, 1.1.1.2 blocks malware, and 1.1.1.3 blocks both malware and adult content. It's a service that does exactly what it's supposed to do.
3.
by qzzi 6mo ago
Simply removing the GIL and running 10,000 threads seems very unlikely.
4.
by qzzi 10mo ago
I've been hacking professionally for 30 years and I know what to look for. Anthropic's report is garbage. Period.
5.
by qzzi 11mo ago
Compared to what? What gives you all that, and what prevents you from having it with tables?
6.
by qzzi 1y ago
I'm pretty sure they're talking about reference counting that depends on the arguments, not about optional arguments or invalid argument combinations.
7.
by qzzi 1y ago
C and Python automatically concatenate string literals, and Rust has the concat! macro. There's no problem just writing it in a way that works correctly with any indentation. No need for weird-strings. " one\n" "
8.
by qzzi 1y ago
They aren't comparing those crimes. You don't get to pick and choose where laws should matter based on whether you personally like the item being banned. Your "bad guys will do it anyway" argument doesn’t hold.
9.
by qzzi 2y ago
The point is obviously that the counter is centralized, and it relates to the previous example where is no concurrency. The need for synchronization when sharing data across threads is mentioned just below that.
10.
by qzzi 2y ago
In the right place, but maybe at the wrong time. You can expect +1 and always be right, when the value should be +10.
11.
by qzzi 2y ago
No, the debugger does not get involved in preprocessing. When you write "a = __LINE__;", it expands to "a = 10;" (or whatever number) and is compiled, and the debugger has no knowledge of it. Debugging information, inclu
12.
by qzzi 2y ago
The __LINE__ macro, like all other macros, is expanded during the preprocessing of the source code and is not handed to the debugger in any way.
13.
by qzzi 2y ago
This is the place where the listening socket is initialized, and you can see that if the port is 0, it doesn't do anything. Are you observing different behavior?
14.
by qzzi 2y ago
It is a commercial product and it is their goodwill to offer licenses for free. They don't have to do it at all, Mr. Entitled.
15.
by qzzi 3y ago
> you know any actual tab character in the input is a field separator, and then you can go through the fields to put back the escaped ones The "\t" in "split" is not a "slash-tee" but an actual tab character
16.
by qzzi 3y ago
No.
17.
by qzzi 3y ago
I don't know how they define `MAX`, but I'm guessing it's a typical "a>b?a:b". In function `elf_read_pintable` the `npins` is defined as signed int and `sysno` as unsigned int. So this comparison will be unsigned