gmkiv

8 ms·

1.
by gmkiv 3y ago
How does ALiBi compare to rotary positional embeddings? That method makes similar claims. I find ALiBi much easier to understand, but that’s probably not the best reason to chose it over other methods.
2.
by gmkiv 3y ago
> I'm not sure if Burton was a Luddite who didn't believe in statistics or the scientific method, or if he didn't care about learning from his tests. It's possible. It's also possible that he had a good sense of
3.
by gmkiv 4y ago
The link you provide seems to say that the cost of wholesale PV + storage is $85-$158 (bottom figure, line 3). Am I misreading that? I’ve noticed that many solar+storage installations these days are 4-hour storage, so not sufficient for bas
4.
by gmkiv 4y ago
It's not obvious how to translate this figure into a standalone plant cost. The COB study is quoting the acquisition cost premium of a nuclear ship over a non-nuclear ship. I believe that estimate is the premium for taking a non-nuclea
5.
by gmkiv 5y ago
They don't want to exacerbate racial disparities, which is noble. They could have used that as their sole justification, but for some reason they also try to say that the crime datasets are inaccurate. Their reasoning for this is sur
6.
by gmkiv 5y ago
The value is to inform the larger discussion of the risks and benefits of gain of function research.
7.
by gmkiv 5y ago
The state (phase) of the received photon will depend on the position of the receiver. Even if you have a perfect quantum hard drive, you still need to maintain the position of your receivers to within a wavelength. That will be hard to do i
8.
by gmkiv 5y ago
I shudder to think of the difficulty in maintaining phase coherence at optical wavelengths for the baselines they mention in this article.
9.
by gmkiv 6y ago
The directive to strike a positive tone could be nefarious or benign; we can’t tell from the info in the article. Every research paper has a tone that depends on the personality of the author - I’ve seen it even in my dry field of quantum o
10.
by gmkiv 6y ago
I happen to agree with you, the observer is a quantum system must get entangled with the quantum system, but that still doesn't explain probabilities. If you prepare a system - say sqrt(1/3) spin-down + sqrt(2/3) spin-up, and