enizor2

6 ms·

1.
by enizor2 5mo ago
Only if you use regular metal discs. Using diamond discs, you break through in less than a minute in those locks: [1] Comparing with your CyclyngWeekly link: - the Litelock X3 goes from 5min to cut only 50% of the shackle to 23s fully cut.
2.
by enizor2 7mo ago
Absolutely not. He refused to defend his classic title in April 2023, citing a lack of motivation for this format. The "Jeans" controversy happened during the Rapid championship in December 2024, nearly two years after. It's
3.
by enizor2 2y ago
What do you mean ? A K-d tree handles k dimensions. Generating a useful 2-D representation (=projection) of more dimensions is the hard part.
4.
by enizor2 2y ago
The BYTE_STREAM_SPLIT is a Z-order (also known as Morton encoding). As it is better a preserving locality, it usually performs really well compared to classical "orthogonal" orders. It also is really simple to implement as it boil
5.
by enizor2 2y ago
> If you zoom in sufficiently at x = 0, f(x) = sin(x) looks indistinguishable from f(x) = x, whereas g(x) = cos(x) looks indistinguishable from g(x) = 1. You can't use the plot as you only know the triangle definition yet. (And &qu
6.
by enizor2 2y ago
I quote the second paragraph of the Derivatives section. (which was edited to a better, but not yet enough, sin(h)≈h and cos(h)≈1 when h is close to zero). I perfectly understand that around 0, sin(x) ~ x and cos(x) = 1 + o(x) but it isn&#x
7.
by enizor2 2y ago
Could you expand on getting the differential equation from your definition? I don't really where to start from it.
8.
by enizor2 2y ago
I do not understand this consideration: > By considering a triangle with hypotenuse 1 and a very small “opposite” side, it’s not hard to see geometrically that sin(x)≈x and cos(h)=x when x is small I fail to see how you can "see&qu