albert_roca

11 ms·

1.
Ask HN: Probability of deriving 7 constants to <10ppm from discrete geometry
2 points by albert_roca 9mo ago|0 comments
2.
by albert_roca 9mo ago
- Why 4? It's not random. It is derived from the structural constant w = 2 as a topological constraint of the three-dimensional topology. Radius scales as w^2 = 4. - Why tetrahedron? Mass is defined as volume. The tetrahedron is the si
3.
by albert_roca 9mo ago
Undefined/non-consensual prompt.
4.
by albert_roca 9mo ago
Thanks for running this on GPT 5.2. It is fascinating to see AI critiquing AI-assisted work. The critique regarding hidden degrees of freedom is a fair point. However, in curve-fitting, parameters are continuous: one can choose 4.1 or 3.9 t
5.
by albert_roca 9mo ago
Because AI has been in the center of the debate so far, I ran your comment through my AI system, and it concluded that you captured the essence of the model perfectly: the polyhedra are topological standing waves, and the edges are nodal li
6.
by albert_roca 9mo ago
I am referring to other comments in this thread that dismissed the proposal purely based on the use of AI tools. My comment about prejudice was not directed at you.
7.
by albert_roca 9mo ago
Fair enough. However, it is practically impossible to complete such a task in a human lifetime. But even if it were possible, the main point stands: using computers to perform calcualtions is standard scientific practice. Discrediting a pro
8.
by albert_roca 9mo ago
The model shows that the surface and volume of an object scale with mass such that electrostatic and gravitational acceleration can be explained through this scaling relationship. This is considered a geometric or structural cost: C_s ~
9.
by albert_roca 9mo ago
Absolutely not. Results don't depend on who performed the calculation or how it was done. Can you solve 12,672 Feynman diagrams by hand?
10.
by albert_roca 9mo ago
This seems properly copied and pasted. Good job. I guess we agree that AI is already playing a central role in science, and physics is no exception.
11.
by albert_roca 9mo ago
Can you share the results of your analysis by association? Or was it an instant mental calculation?
12.
by albert_roca 9mo ago
That's precisely what the numbers show. "Pred:", predicted value. "Exp:", experimental value. "Diff", difference.
13.
by albert_roca 9mo ago
Your contribution is the opposite of "something".
14.
by albert_roca 9mo ago
I have reported nothing but numerical results. Making assumptions about me instead of looking at the numbers says more about your background than it does about mine.
15.
Is the Standard Model overfitting or am I curve-fitting?
3 points by albert_roca 9mo ago|28 comments
16.
by albert_roca 9mo ago
64 is dimensionless. It comes from the model's holographic scaling law, where mass scales with surface complexity (m ∼ 4^i). The proton appears at i = 32. 4^32= (2^2)^32 = 2^64 2^64 seems to be the minimum information density re
17.
by albert_roca 9mo ago
The model identifies the proton mass stability at the 64-bit limit (2^64). Since gravitational interaction scales with m_p^2 , the hierarchy gap corresponds to the square of that limit: (2^64)^2 = 2^128 The geometric derivation invol
18.
Gravity coupling matches the 128-bit integer limit to 6 ppm
2 points by albert_roca 9mo ago|4 comments
19.
by albert_roca 9mo ago
You put the following sentence in quotes: "12,672 diagrams is brute force. Achieving 63 ppm with one term (a_μ = α / 2π + α^2 / 12) is elegant". I never made that specific claim, nor does the word "elegant" app
20.
by albert_roca 9mo ago
I cannot be too categorical in the definitions because sometimes numerical findings appear before they can receive the proper interpretation. This is normal in the development of any new theory. No LLM induced me to make this proposal. In f
21.
by albert_roca 9mo ago
You transcribed the formula incorrectly. The term is -(alpha / 24). You calculated -1 / (24 · alpha). The correct derivation is: 1 / alpha = S - (alpha / 24) 1 = S · alpha - (alpha^2) / 24 alpha^2 - 24 · S ·
22.
by albert_roca 9mo ago
The "Equilibrium Mass" mz is Not Physical The claim that Fe = Fg at some special mass mz = √(α·mP) ≈ 1.86×10⁻⁹ kg is mathematically true but physically meaningless m_z is the geometrical point of transition between regime
23.
by albert_roca 9mo ago
This is moving the goalposts, but ok. The model matches the international standard of CODATA 2022 to 0.005 ppm. If and when this value is updated, the prediction can be re-evaluated. Until then, I stick to the standard.
24.
by albert_roca 9mo ago
It's not circular. It rearranges into a standard quadratic equation: x^2 − 24Sx + 24 = 0. α is derived as the root of this equation.
25.
by albert_roca 9mo ago
Hm. You are correct about m_p and m_e. That is indeed a sloppy mistake in the script. Bad code. However, the hypothesized closed value of G stays the same.
26.
by albert_roca 9mo ago
The numbers seem to follow a geometric logic: Alpha / 3: The "3" represents the spatial dimensions. +1 and squared: 1 is the undistorted space, and it is squared because space intervals are quadratic, like in the Pythagorean
27.
by albert_roca 9mo ago
The calculation uses m_p , which is independent of G. Deriving G to 8 ppm from m_p is not necessarily "meaningless", or at least it's statistically non-trivial. It is not just "G = G". You mention the "uncharge
28.
by albert_roca 9mo ago
Valid question. The significance is that the 4^32 scaling factor emerged earlier in the model as a geometric constraint, and 4^64 appears in this equation, apparently because G is inversely proportional to the square of m_P. Hitting G withi
29.
by albert_roca 9mo ago
EXPECTED OUTPUT: OBJECT | UNIFIED | GR | DIFF % ----------------------------------------------------------------- Electron | 2.53264e+22 | 2.53262e+22 | 0.00084794 Proton | 2
30.
Show HN: G=(hbar*c*2*(1+alpha/3)^2)/(m_p^2*4^64) ≈ 6.6742439706e-11 (8 ppm)
2 points by albert_roca 9mo ago|30 comments

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