5 ms·
Success = (number of attempts) × (probability of success each time)
- azatom 25d agoI didn't read the article, I don't think these kind has any value, but if you are here.. :) i think it is rather binary, so P_overall_success = 1 - (1 - P_success) ^ #attempts and expected number of first success: n = 1 / P_success
- Arodex 25d agoI don't see "cost" mentioned anywhere there.
- AnimalMuppet 25d agoThat determines how many attempts you can buy.
- Ariarule 25d agoSurprised there's not a specific mention of learning by doing, which means probability of success is not static, when this is _just_ under the surface of the content of this post. They did kind of hint at this with the "Each attempt... a little better than the last."