5 ms·
Only meaningful if code+data deterministically reproduce the weights. At that point, the weights are just the cached output. Which has value since it's costly
by brianstrimp 2y ago
Only meaningful if code+data deterministically reproduce the weights.
At that point, the weights are just the cached output. Which has value since it's costly to produce from code+data.
- frabcus 2y agoI don't think it needs to be deterministic - and if it isn't, having the data and code becomes even more important! Compilers generally aren't deterministic (see the reproduceable build movement), yet we still use their output binaries.
- brianstrimp 2y ago[dead]