7 ms·
Because you've defined "safety" to encompass several orthogonal concepts and as such is meaningless. If you look at each axis on it's own ( type safety, memory
by freyrs3 12y ago
Because you've defined "safety" to encompass several orthogonal concepts and as such is meaningless. If you look at each axis on it's own ( type safety, memory safety, exceptional safety ) then Haskell will come out as safer than nearly any other available tool.