17 ms·
Does this mean that a 10^13 reliability has 320% chance of failure? EDIT: in any case the correct calculation should be http://www.wolframalpha.com/input/?i=%2
by lindenr 12y ago
Does this mean that a 10^13 reliability has 320% chance of failure?
EDIT: in any case the correct calculation should be http://www.wolframalpha.com/input/?i=%281-%2810^-14%29%29^%288*4*1024^4%29 http://www.wolframalpha.com/input/?i=%281-%2810^-14%29%29^%2... which gives a 30% chance of failure, versus http://www.wolframalpha.com/input/?i=%281-%2810^-15%29%29^%288*4*1024^4%29 http://www.wolframalpha.com/input/?i=%281-%2810^-15%29%29^%2... for a 3.5% chance.
- ars 12y ago320% would mean you find 3 wrong bits each time you read the disk. I was calculating the expected number of wrong bits per full read of the drive. You calculated the chance of a perfect read which is similar but not the same.
- lindenr 12y agoAh, I see. Could you edit your post to reflect this? As it stands it is very easy to misinterpret.
- ars 12y agoYou can only edit for a little over an hour, and it's been three. I thought "of one bit being wrong" said it, but I can see how you misread it. Hopefully people will read the thread and see these replies as well.