Right, it's (re) defined every time you call 'foo2' but that's a different scenario than the one written in the article (hadn't you had 'foo2' and only 'foo' th

Right, it's (re) defined every time you call 'foo2' but that's a different scenario than the one written in the article (hadn't you had 'foo2' and only 'foo' then you'd have the same time in all your calls to the function without supplying arguments).