5 ms·
That's not what they mean. The usage they are discussing is more like this, I believe. In a functional context, instead of doing: print expensive_computati
by Ideka 12y ago
That's not what they mean. The usage they are discussing is more like this, I believe. In a functional context, instead of doing:
print expensive_computation(), expensive_computation()
You can do:
(lambda x: print x, x)(expensive_computation())
Which would be equivalent to, with an imaginary let syntax:
(let x be expensive_computation(): print x, x)