Let's put some algebra/order into this... Bellman-Ford works for any totally ordered group (G,+), such that a+b<=a+c if b<=c. What logarithm does is just a ord

Let's put some algebra/order into this... Bellman-Ford works for any totally ordered group (G,+), such that a+b<=a+c if b<=c. What logarithm does is just a order preserving homomorphism from (R,*) to (R,+).