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I don't really get this. This is how it should work, no? The point is to type the word correctly; if you miss a letter or mistype, and keep typing, then yeah, i
by squigz 25d ago
I don't really get this. This is how it should work, no? The point is to type the word correctly; if you miss a letter or mistype, and keep typing, then yeah, it's several mistakes in a row?
- hnlmorg 25d agoLetters in a row maybe. But one mistyped word shouldn’t cause subsequent words to appear mistyped
- squigz 25d agoThat doesn't seem to happen on typ.ing or really any other typing site I know of.
- eviks 25d agoNo, the point is to type the word a you'd do in real life, that is, make the mistake, finish word/sentence/thought and then correct. And the correction would be changing just the first mistake
- squigz 25d ago> the point is to type the word a you'd do in real life, I don't really know about that. I think the point is to practice typing, and that may or may not reflect how you type in everyday life. For example, most people don't spend their time typing random words without numbers or punctuation :) In any case, are you saying that if you correct a word during one of these tests, it simply should not count as a mistake? Because if not, then I don't see what the problem is again - typ.ing and most other sites note corrections, and distinguish between corrected and uncorrected mistakes. If so, I guess we might just disagree on what the point of these exercises is.
- IceDane 25d agoI don't see how this can be so difficult to understand. If the second word in my first sentence were misspelled, does that make every other word or letter that comes after wrong?
- Graziano_M 24d agoSay I type out the Iliad absolutely perfect, but on the first character I accidentally type an extra 'R'. Would you say that I typed it 0% correctly? Because this, and many other typing testers would score it that way, simply because every character after that is now shifted over by one. Ironically, later on missing a character would actually improve your score.