>Perhaps this is not surprising, as the exponent of 1.5 resembles the equation for curvature of a parametric curve : k = x' × x'' / (x'•x')^(1.5) Hindsight is

>Perhaps this is not surprising, as the exponent of 1.5 resembles the equation for curvature of a parametric curve : k = x' × x'' / (x'•x')^(1.5) Hindsight is really something. Of course we usually write the denominator as |x'|^3 but once you see it, it makes sense.