5 ms·

Don't know adding, but multiplication has diagram on the last page of the PDF. xy = eml(eml(1, eml(eml(eml(eml(1, eml(eml(1, eml(1, x)), 1)), eml(1, eml(eml(1,

by nick238 5mo ago

Don't know adding, but multiplication has diagram on the last page of the PDF. xy = eml(eml(1, eml(eml(eml(eml(1, eml(eml(1, eml(1, x)), 1)), eml(1, eml(eml(1, eml(y, 1)), 1))), 1), 1)), 1) From Table 4, I think addition is slightly more complicated?

Charon77 5mo ago
x+y = ln(exp(x) * exp(y)) exp(a) = eml(a, 1) ln(a)=eml(1,eml(eml(1,a),1)) Plugging those in is an excercise to the reader
- jcgrillo 5mo ago
  might need to turn the paper sideways
- freehorse 5mo ago
  You use multiplication in the first line, which you have not expressed through eml yet. Because of how exp and log turn addition into multiplication and vice versa, once you have the one, you get the other easily.
simplesighman 5mo ago
Thanks for posting that. You had a transcribing typo which was corrected in the ECMAScript below. Here's the calculation for 5 x 7: const eml = (x,y) => Math.exp(x) - Math.log(y); const mul = (x,y) => eml(eml(1,eml(eml(eml(1,eml(eml(1,eml(1,x)),1)),eml(1,eml(eml(1,eml(y,1)),1))),1)),1); console.log(mul(5,7)); > 35.00000000000001 For larger or negative inputs you get a NaN because ECMAScript has limited precision and doesn't handle imaginary numbers.
- xigoi 5mo ago
  > For larger or negative inputs you get a NaN because ECMAScript has limited precision and doesn't handle imaginary numbers. This also shows why EML is not practical for computation.