6 ms·

If it's an "array of strings AND numbers", then it should not be allowed to call the function with a string[], because those are different types.

• clownstrikelol 5mo ago
  That’s barely scratching the surface. In TypeScript the following is also valid: class Something{ value: Number } class SomethingElse{ value: Number foo: String bar: SomeOtherThing[] } function AddSomething(v: Something) { v.value += 1; } var ex = new SomethingElse{ value: 3, foo: “TypeScript is fake types”, bar: [] }; AddSomething(ex); Why does it work? Because in TypeScript as long as you have a “shape” that fits, it’s the “same type.” Complete and utter insanity to me, to pretend there’s any real type checking, when types are entirely fake and made up.
  • saghm 5mo ago
    That's because it's structurally typed (as opposed to nominally typed). I don't happen to prefer it, but I don't think it's fair to conflate that with unsoundness like the example given above; it's totally possible to have a sound structural type system. TypeScript doesn't happen to be sound, but it's not because of that.
    • teaearlgraycold 5mo ago
      Structural typing is great. It's the verified version of duck typing.
      • LelouBil 5mo ago
        You can even get nominal typing with branded types if you need it. (Like for the newtype pattern)
• saghm 5mo ago
  That would be the sound way to do things, but it's also surprisingly common for arrays for some reason. It also doesn't get checked compile time in Java, although it does throw an exception because the arrays are type-enforced at runtime at least. This compiles fine: class A {} class B1 extends A {} class B2 extends A {} public class MyClass { public static void main(String args[]) { A[] array = new B1[1]; array[0] = new B2(); } }