6 ms·
It's likely that "knows" has no separate definition, but is used in some definition of "operator". If so, then "operator" should probably connect to "know", and
by codeflo 6mo ago
It's likely that "knows" has no separate definition, but is used in some definition of "operator". If so, then "operator" should probably connect to "know", and "knows" shouldn't appear in the graph at all. But calling that edge case "broken" is a bit harsh, I think.