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What is the name of this operator: “--”?
- rwolf 14y agoThe title is missing a >. Should be "-->"
- QuarkSpark 14y agoFor some reason it changes the "-->" back to "--" I tried many times/ways to include the entire operator before giving up & just posting it..
- sukuriant 14y agoWhat about > ?
- The_Egg_Man 14y agoCould someone break this down and explain it to me? [1] It looks hilariously atrocious yet interesting at the same time. [1]: http://stackoverflow.com/questions/1642028/what-is-the-name-of-this-operator/2860927#2860927 http://stackoverflow.com/questions/1642028/what-is-the-name-...
- ctdonath 14y ago#define as ;while ... do printf("n is %d\n", n) as ( n --> 0); Parses to (white space adjusted for clarity): do printf("n is %d\n", n); while ( n-- > 0);
- dmbass 14y agoThe preprocessor replaces the macro "as" with ";while" creating a do-while loop. do { printf("%d",x); } while (x-- > 0);
- stephen_g 14y agoBasically, somebody sees some code with two operators (decrement and less than) with no whitespace between them and thinks it's a single operator. The answer that shows it with the brackets is probably the clearest: while ((x--) > 0) { ... } The compiler sees that as the same as (x--> 0) So it checks if x is more than zero and then decrements it each loop iteration.
- sukuriant 14y agoThis looks mostly like a function that sacrificed readability for brevity, to the detriment of at least one reader.
- halis 14y agoDecrement x = x -1
- antihero 14y agoFrom the thread: while (x --\ \ \ \ > 0) printf("%d ", x); That's fantastic!