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Overengineered in my view, what is wrong with `x | f` is `f(x)`? Then `x | f | g` can be read as `g(f(x))` and you're done. I don't see any reason to make it mo
by sproutini 1y ago
Overengineered in my view, what is wrong with `x | f` is `f(x)`? Then `x | f | g` can be read as `g(f(x))` and you're done. I don't see any reason to make it more complicated than that.
- xigoi 1y agoYou can’t make it work like that in current JavaScript.
- deleted 1y ago[deleted]