7 ms·

This seems so simple but I’m totally not understanding it.. If C = D^2, and you double compute, then 2C ==> 2D^2. How do you and the original author get 1.41D

by dosnem 1y ago

This seems so simple but I’m totally not understanding it.. If C = D^2, and you double compute, then 2C ==> 2D^2. How do you and the original author get 1.41D from 2D^2?

yberreby 1y ago
If C ~ D^2, then D ~ sqrt(C). In other words, the required amount of data scales with the square root of the compute. The square root of 2 ~= 1.414. If you double the compute, you need roughly 1.414 times more data.
- dosnem 1y ago
  Thanks for clarification!