8 ms·
Or, even better, also from the cookbook: {(2#x)#1,x#0} But this really borders on obfuscation :P
by gabiteodoru 1y ago
Or, even better, also from the cookbook: {(2#x)#1,x#0} But this really borders on obfuscation :P
- leprechaun1066 1y agoThat does require someone to know that the take operator continues to treat the y list as circular when x is a list. I think this form might be a bit easier: {(x,x)#(x*x)#1,x#0}
- gabiteodoru 1y agoBut then you're not flexing your q muscles. Btw this is from the cookbook, these obfuscated patterns are actually recommended! https://code.kx.com/phrases/matrix/#identity-matrix-of-order-x https://code.kx.com/phrases/matrix/#identity-matrix-of-order...