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No idea why this happened. Perhaps Math.Pow(x,y) was implemented as 2**(y*log2(x)) without writing special code to deal with the case where x is negative real a
by The_suffocated 1y ago
No idea why this happened. Perhaps Math.Pow(x,y) was implemented as 2**(y*log2(x)) without writing special code to deal with the case where x is negative real and y is integer?
- rich_sasha 1y agoIn fairness, the general power function might well be complicated. Dealing with fractional base and exponent, signs (-1^2 makes sense but -1^0.5 doesn't in real numbers). I don't know how that works in code but I can see how this gremlin sneaks in. I don't see how it gets past the test suite though.