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How to Cheat with Math – The Russian Cards Problem
- deleted 2y ago[deleted]
- rawling 2y agoDoes "the sum of my cards modulo 7 is [x]" work? It should let Bob know what the missing card is but I can't tell if it conveys sufficiently little information to Eve for it to count.
- BoiledCabbage 2y agoIs the modulo required? Is just "The sum of my cards is x" sufficient?
- ashdnazg 2y agoYes. For instance, if a player says the sum of their cards is 3, Eve immediately knows they have cards 0, 1 and 2.
- deleted 2y ago[deleted]
- ashdnazg 2y agoThe article's definition of not revealing information is a bit unclear, but if we understand it as Eve not knowing who holds any single card, your solution seems to work. At least assuming the following code is correct :) import itertools import functools for eve_card in range(7): cards_left = set(range(7)) cards_left.remove(eve_card) mod_to_cards = [[], [], [], [], [], [], []] for c in itertools.combinations(cards_left, 3): mod = sum(c) % 7 mod_to_cards[mod].append(set(c)) for combs in mod_to_cards: i = functools.reduce(lambda x, y: x.intersection(y), combs) if len(i) != 0: print("intersection", eve_card, combs, i) u = functools.reduce(lambda x, y: x.union(y), combs) if len(u) != 6: print("union", eve_card, combs, u)
- ninja3925 2y agoThe advised reader could devise a solution using public / private key where: - Alice communicates her public key - Bob communicates his - Alice encoders her cards with Bob’s public key - Bob does the same Problem solved!