If the length of a meter were defined as the length of a seconds pendulum [1], then g would equal exactly π². From the pendulum equation: `T = 2π√(L/g)` subst

If the length of a meter were defined as the length of a seconds pendulum [1], then g would equal exactly π². From the pendulum equation: `T = 2π√(L/g)` substitute T = 2 s and L = 1 m: `2 s = 2π√(1 m / g)` solve for g: `g = π² m/s²`. This holds up in any strength of gravity, but the length of a meter would be different depending on it. [1]. This actually was proposed by Talleyrand in 1790. Imagine the world if this were true!