5 ms·

Why is number 1 better than just: [x*2 for x in range(1, 11)]

• antonios 14y ago
  It isn't.
• eieio 14y ago
  I felt the same about number 3. [x in tweet.split() for x in wordlist] Seems better to me than map(lambda x: x in tweet.split(),wordlist) Although the natural thing for me to do would be [x for x in wordlist if x in tweet] Which both generates a list of words instead of booleans(['scala', 'sbt'] instead of [True, False, False, False, False]) and also matches the 'sbt' in tweet.
  • saintfiends 14y ago
    or just: set(tweet.split()) & set(wordlist)
• shoo 14y ago
  Or with numpy: 2 * numpy.arange(1, 11) The usual notation for working with elements of vector spaces is nice when working with arrays of numbers.