4 ms·
In the example they have > const urlstring = "this is not a URL"; > const not_a_url = URL.canParse(urlstring) && new URL(urlstring); Why would you need the l
by salil999 2y ago
In the example they have
> const urlstring = "this is not a URL";
> const not_a_url = URL.canParse(urlstring) && new URL(urlstring);
Why would you need the latter part of the condition? Couldn't it just be this?
> const isValidURL = URL.canParse(urlstring);