5 ms·
It’s fairly common to use two hash functions and then compute the remaining n hashes as hn(x) = h1(x) + n * h2(x). Paper: https://link.springer.com/chapter/10.
by boyd 3y ago
It’s fairly common to use two hash functions and then compute the remaining n hashes as hn(x) = h1(x) + n * h2(x).
Paper: https://link.springer.com/chapter/10.1007/11841036_42 https://link.springer.com/chapter/10.1007/11841036_42