doesn't is suffice to say that functions meet all the prerequisites of a vector space? f + g = g + f f + (g + h) = (f + g) + h f + -f = 0 (a * b) * f = a *

doesn't is suffice to say that functions meet all the prerequisites of a vector space? f + g = g + f f + (g + h) = (f + g) + h f + -f = 0 (a * b) * f = a * bf a (f + g) = af + ag (a + b) * f = af + bf