6 ms·

> x/2 + y/2 + (x & y & 0x01) This returns -1 for x = INT_MIN and y = INT_MAX were the answer should be 0 (for an example). so not a correct solution

• slymon99 4y ago
  Isn't (32 bit) INT_MAX 2^31-1 and INT_MIN -2^31, so this is an acceptable solution (since the decimal average is -0.5)?
  • pksadiq 4y ago
    > since the decimal average is -0.5 The C standard says: When integers are divided, the result of the / operator is the algebraic quotient with any fractional part discarded (This is often called ‘‘truncation toward zero’’). So it should be 0 (as per C standard, not sure what C++ standard says)
    • a1369209993 4y ago
      The question is midpoint, not division, so that's irrelevant in the first place, and even if were division, the standard is wrong.