4 ms·
Nope, the threads run in parallel. The variable x is mutably borrowed only once by the second thread. The variable a is immutably borrowed twice, so there is no
by DenseComet 4y ago
Nope, the threads run in parallel. The variable x is mutably borrowed only once by the second thread. The variable a is immutably borrowed twice, so there is no issue.
- theptip 4y agoAre you certain? From the docs on https://doc.rust-lang.org/stable/std/thread/struct.Scope.html#method.spawn https://doc.rust-lang.org/stable/std/thread/struct.Scope.htm..., > If the join handle is dropped, the spawned thread will implicitly joined at the end of the scope. Plus the comment says > // We can even mutably borrow `x` here, // because no other threads are using it. Which doesn’t line up with another thread having a read-only borrow on it. Anyway not at my machine to test right now, I could be wrong.
- theptip 4y agoOh never mind, I’m completely misreading. Thanks for the pointer.
- deleted 4y ago[deleted]
- Tuna-Fish 4y agox is not used by the other thread, a is. > If the join handle is dropped, the spawned thread will implicitly joined at the end of the scope. "end of scope" here refers to the end of the closure, after the second thread is spawned. You can trivially show that the threads exist in parallel by adding waits.