6 ms·
No need to complicate things with obscure units. You have: 40 MW/30% / (10722.2 W*hr/L) You want: L/hr 40 MW/30% / (10722.2 W*hr/L) = 12435.259 L/hr
by m55au 4y ago
No need to complicate things with obscure units.
You have: 40 MW/30% / (10722.2 W*hr/L)
You want: L/hr
40 MW/30% / (10722.2 W*hr/L) = 12435.259 L/hr
- dredmorbius 4y agoGNU Units has builtins for some standard energy equivalent units, specifically "tonoil" and "barreloil". "litreoil" doesn't seem to be included by default (though it can be added via a local configuration file). literoil = 1 barreloil * liter/barrel And the calculation gives me ...10.69 kWh/L The barreloil value is for crude, diesel may have a slightly higher net energy density. But we're good to 3 sig figs. I could have bypassed the tonoil step and calculated thermal energy in barreloil directly though saving another conversion. Otherwise I'd have to remember energy density/L of diesel fuel. I've added the definitions for litre, pound, and kg oil and can now run: $ units --terse '40 MWh/30%' literoil 12470.969 The fun part though, at least for me, is showing how to do conversions with GNU units, and the equivalences which become apparent doing so.
- m55au 4y agoI looked around a bit in "definitions.units" and there are actually energy densities in there for various fuel sources, including diesel. You have: 1 diesel You want: Wh/L 1 diesel = 10103.465 Wh/L Slightly different value than in Wikipedia, but close enough.
- dredmorbius 4y ago*blink* TIL, there are! Thanks. (For the curious, the definitions file is ~7500 lines, there's a lot in there. GNU version. For those on MacOS, the stock BSD units offers far less.)