6 ms·

I agree. 68k was one of the most orthogonal architectures ever.

• inkyoto 5y ago
  After the PDP-11 architecture, yes.
• Taniwha 5y ago
  well except for the two sorts of registers
  • Joker_vD 5y ago
    Three, starting with 68040.
    • a-priori 5y ago
      And likely far more by now, had it become the PC instruction set architecture. The x86 instruction set was also simpler back in the late 70s, in the 8086 era when the Motorola 68000 was first released, than it is now. Back then it only had the one register width (16-bit, e.g. "ax"), whereas now it has the 32-bit series (e.g. "eax") series and the 64-bit series (e.g. "rax"). It also now has SIMD, SSE/AVX, virtualization support, and other technologies. Back then it just had one operating mode (real mode), whereas now it has protected mode, long mode, system management mode, and a few other intermediate modes (e.g. "unreal mode"). So a lot of the complexity that x86 has now was introduced after that decision was made. It's definitely conceivable that the 68000 line would have developed similarly had it been chosen instead of x86 for the PC.
      • coldacid 5y ago
        8086 let you address the upper and lower halves of the 16-bit registers as well, so don't trick yourself into thinking there was just one register width available in the sense that everything could only be treated as 16-bit words.
        • colejohnson66 5y ago
          Many 8 bit processors had the same “feature”. For example, the Z80’s 8 bit registers were internally just halves of a 16 bit register.