5 ms·
It's shame that after that entire explanation (the moon-earth firepole one) that he never actually answers the question of how long it would take...
by bobbles 5y ago
It's shame that after that entire explanation (the moon-earth firepole one) that he never actually answers the question of how long it would take...
- saagarjha 5y agoMost of the time goes into climbing, which he estimates as taking "several years".
- LorenPechtel 5y agoYou can't climb the pole. Tsiolkovsky's rocket equation rules, you can't bring enough food to climb the pole. (Yes, I know, it's not a rocket. It really should be called Tsiolkovsky's logistics equation--it applies to any situation where you have to bring along your power source, whether it's a rocket or not.)
- Sohcahtoa82 5y agoReally? I must be misunderstanding something then. The Earth-Moon L1 point is ~63 km from the Moon. Let's say me and my gear weigh 200 lbs, and the Moon's gravity acceleration is 1.62 m/s^2. 63 km * 200 lbs * 1.62 m/s^2 gives a potential energy of only 2,213 kcal. The human body is only 18-26% efficient [0] at converting food into energy, so we're probably looking at around 10-13,000 calories. Depending on what you're eating, that's 4-10 lbs of food. Obviously, I'm ignoring the time it would take to climb that far, but in terms of energy, it seems reasonable that a human could carry enough good with them, unless I'm gravely misunderstanding something. I'm guess that assuming "potential energy" means "the energy needed to move X pounds to Y height at Z gravity" is incorrect. [0] https://physics.stackexchange.com/questions/46788/how-efficient-is-the-human-body https://physics.stackexchange.com/questions/46788/how-effici...
- saagarjha 5y agoI believe your L1 distance is off by about three orders of magnitude.
- Sohcahtoa82 5y agoOh crap you're right, not sure how I got such a low number.
- saagarjha 5y agoThe rocket equation is not necessarily relevant here, because you can have the pole be a space elevator that brings you food.