15 ms·
3678 packets / 2.5 hours = One packet every 2.44 seconds * 1500 byte MTU = 3.5KB/s Yup, a 4800 baud modem.
by thelema314 15y ago
3678 packets / 2.5 hours = One packet every 2.44 seconds * 1500 byte MTU = 3.5KB/s Yup, a 4800 baud modem.
- tedunangst 15y agoYou don't multiply packet size by interval, you divide (or multiply by the inverse). And baud is measured in bits. But the numbers come out close anyway. 3678 / (2.5 * 3600) * 1500 * 8 = 4904.
- moe 15y agoDid 4800 baud modems even exist in volume? I just checked wikipedia and there's indeed a protocol for them, but I've never seen one in the wild. In my day it was 300, 1200, 2400, 9600, 14400, 16800, 19200, 28800, 33600, 56k ... So, back on topic, wouldn't it be more likely he was channel bonding two 2400 baud modems?