7 ms·
That's simply a logical fallacy: P => Q does not imply (not P) => (not Q). Here: "If it is inaccurate, then it is wrong" does not imply "If it is accurate, then
by NoKnowledge 5y ago
That's simply a logical fallacy: P => Q does not imply (not P) => (not Q). Here:
"If it is inaccurate, then it is wrong" does not imply "If it is accurate, then it is right."