6 ms·
Looks like there a typo in the exploit() function? They have this variable declaration in the beginning: static const short port_base = 0x434; However they us
by Eugr 6y ago
Looks like there a typo in the exploit() function?
They have this variable declaration in the beginning:
static const short port_base = 0x434;
However they use "port" variable when making calls:
__outbyte(port+3, 0);