You can express a type as one of many interfaces, or use discriminated unions (https://www.typescriptlang.org/docs/handbook/advanced-types.html#discriminated-un

You can express a type as one of many interfaces, or use discriminated unions (https://www.typescriptlang.org/docs/handbook/advanced-types.html#discriminated-unions https://www.typescriptlang.org/docs/handbook/advanced-types....) by using some unique version key to identify each interface. Then you'll have all the goodness of types back :)