4 ms·
python: sum([n * n for n in range(1,5,3)])
by lightsighter 7y ago
python: sum([n * n for n in range(1,5,3)])
- marai2 7y agohaskell: sum [n^2 | n <- [1,3..5]] I just remembered haskell's "range" operator ".." can also take a step size. ['a', 'd' .. 'z'] => "adgjmpsvy"