6 ms·

Sorry, is it xz + yz = x(y + z) when using operators? That seems wrong.

• quietbritishjim 8y ago
  I don't know any Lisp, but I would decode (= (* x (+ y z)) (+ (* x z) (* y z))) As x*(y + z) = x*z + y*z e.g. (+ y z) means you add y and z with highest priority.
  • grenoire 8y ago
    Which is incorrect, they aren't equal.
    • nanaya 8y ago
      Well, technically it solves to x = z when y <> 0 and any x, z when y = 0 though I'm not sure if that's the original intention.
    • Retra 8y ago
      That is probably not a statement of equality, but a boolean test for it.