Something like... (Pseudocode) for( i= 1,100 ) { if( i%3==0 ) { print( 'Fizz' ) } if( i%5==0 ) { print( 'Buzz' ) } print( '\n' )

Something like... (Pseudocode) for( i= 1,100 ) { if( i%3==0 ) { print( 'Fizz' ) } if( i%5==0 ) { print( 'Buzz' ) } print( '\n' ) } There's no need to treat FizzBuzz as a special case, as if the number is divisible by both it will have already met the conditions of the previous two statements. I wonder if there's some magic you could sprinkle in to the iterator so it only iterates through numbers which are divisible by 3/5, ignoring the rest? It probably wouldn't speed the operation up much (if at all) in this case, in a more complex real world scenario though it's best to look at every angle.