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What's "L-calculus"? And what does "alternative formulations that rely not on the limit of the addition but on the limit of a multiplier" mean? Any resources?
by somezero 9y ago
What's "L-calculus"? And what does "alternative formulations that rely not on the limit of the addition but on the limit of a multiplier" mean? Any resources?
- pitaj 9y agoAn integral can be thought of as the infinite sum of infinitesimal areas below the graph (look up Riemann sums). I think what he is saying is that instead of summing these, you instead to the product. That is, multiply each infinitesimal quantity together.
- qubex 9y agoA derivative is basically how a small addition to the input value changes the output value; this change in output value is also studied in terms of being something “additional” (though it could also be a subtraction). In L-calculus this approach is altered: how does multiplying the input value by a tiny value greater than one change the amount by which the output value gets multiplied? Here’s the relevant Wikipedia page to get you started down the rabbit-hole: https://en.wikipedia.org/wiki/Multiplicative_calculus?wprov=sfti1 https://en.wikipedia.org/wiki/Multiplicative_calculus?wprov=...