7 ms·
f $ x y $ z Basically, f $ x = f x and is applied with lowest operator precedence (0) and is right associative. Therefore, f $ x y $ z = f (x y $ z) = f((x
by scriptdevil 9y ago
f $ x y $ z
Basically, f $ x = f x and is applied with lowest operator precedence (0) and is right associative.
Therefore,
f $ x y $ z
= f (x y $ z)
= f((x y) z)