6 ms·
As noted above, the collection of all sets cannot be a set in any set theory with specification, regardless of regularity: Call the collection of all sets S.
by gambling8nt 17y ago
As noted above, the collection of all sets cannot be a set in any set theory with specification, regardless of regularity:
Call the collection of all sets S. We specify T by
T=\{x| x \in S \wedge \neg x \in x\}
T is then the subclass of S of sets that do not contain themselves. Thus with specifiction (provable from replacement, or as an axiom by itself), it is contradictory for S to be a set.
If you reject the law of excluded middle, you can have a intuitionist set theory where S is neither a set nor not a set; alternatively, you can have a set theory without specification one constructed based on a type theory might meet this requirement.